目录
思路
代码
思路
代码
#include <iostream>
#include <algorithm>using namespace std;
using LL = long long;const int N = 1e2 + 9;
const int mod = 1e6 + 7;int n,m;
LL a[N];
LL f[N][N];void solve()
{cin >> n >> m;f[0][0] = 1;for (int i = 1;i <= n;i ++) cin >> a[i];for (int i = 1;i <= n;i ++)for (int j = 0;j <= m;j ++)for (int k = 0;k <= a[i] && k <= j;k ++)f[i][j] = (f[i][j] + f[i - 1][j - k]) % mod;cout << f[n][m] << endl;
}