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1、判断列表是否为空或者为NULL

Optional.ofNullable(list).orElse(Collections.emptyList()).isEmpty()  // true=为空或NULL false 不为空或NULL

2、列表包含

List<String> list = Arrays.asList("apple", "banana", "cherry");  
boolean containsApple = list.contains("apple"); // 返回 true  
boolean containsMango = list.contains("mango"); // 返回 false

3、列表排序

对象

List<User> users = new ArrayList<>();
users.add(new User(1L, "张三", 18, 1));
users.add(new User(2L, "李四", 52, 1));
users.add(new User(3L, "王五", 36, 1));
users.add(new User(4L, "赵六", 36, 1));// users.sort(Comparator.comparing(User::getAge));  // 正序
users.sort(Comparator.comparing(User::getId).reversed());  // 倒叙
//        users.sort(Comparator.comparing(User::getAge).thenComparing(User::getId));  // 多条件排序
System.out.println(users);

List<Map<>>

List<Map<String, Object>> resultlist = new ArrayList<>();
Map<String, Object> map1 = new HashMap<String, Object>();
map1.put("id", "1");
map1.put("name", "张三");
map1.put("Score", 86.5);
Map<String, Object> map2 = new HashMap<String, Object>();
map2.put("id", "2");
map2.put("name", "李四");
map2.put("Score", 90.0);
Map<String, Object> map3 = new HashMap<String, Object>();
map3.put("id", "3");
map3.put("name", "王五");
map3.put("Score", 70.5);resultlist.add(map1);
resultlist.add(map2);
resultlist.add(map3);resultlist.sort((o1, o2) -> {Double one = Double.valueOf(o1.get("Score").toString());Double two = Double.valueOf(o2.get("Score").toString());return one.compareTo(two);  //one.compareTo(two)为升序，two.compareTo(one)为降序
});

List String

List<String> headList = new ArrayList();
Collections.sort(headList);

4、列表截取

列表截取 — 左闭右开

List<User> users = new ArrayList<>();
users.add(new User(1L, "张三", 18, 1));
users.add(new User(2L, "李四", 52, 1));
users.add(new User(3L, "王五", 36, 1));
users.add(new User(4L, "赵六", 36, 1));
List<User> new_users = users.subList(0, 3);
for (User newUser : new_users) {System.out.println(newUser);
}

5、列表合并

List<Integer> list1 = Arrays.asList(1, 2, 3);
List<Integer> list2 = Arrays.asList(4, 5, 6);
List<Integer> list3 = Arrays.asList(7, 8, 9);List<Integer> mergedList = Stream.of(list1, list2, list3).flatMap(Collection::stream).collect(Collectors.toList());System.out.println(mergedList);// [1, 2, 3, 4, 5, 6, 7, 8, 9]

6、列表求极值

注意：Collections是java.util包下的

List<Integer> list = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9);
Integer max = Collections.max(list);
Integer min = Collections.min(list);
System.out.println("最大值：" + max + "最小值：" + min);

7、列表转字符串

// 创建一个字符串列表
List<String> list = Arrays.asList("apple", "banana", "cherry");
// 使用String.join()方法将列表转换为字符串
String str = String.join(", ", list);
// 输出结果
System.out.println(str); // 输出: apple, banana, cherry

8、列表去重的四种方式

使用Set接口进行去重，但是需要注意的是这样去重会打乱原来List中数据的顺序。

List<Integer> list = Arrays.asList(1, 2, 3, 2, 4, 4, 5, 5, 6);  
Set<Integer> set = new HashSet<>(list);  
List<Integer> deduplicatedList = new ArrayList<>(set);  
System.out.println(deduplicatedList); // 输出: [1, 2, 3, 4, 5, 6]

使用LinkedHashSet保留插入顺序

List<Integer> list = Arrays.asList(1, 2, 3, 2, 4, 4, 5, 5, 6);  
Set<Integer> set = new LinkedHashSet<>(list);  
List<Integer> deduplicatedList = new ArrayList<>(set);  
System.out.println(deduplicatedList); // 输出: [1, 2, 3, 4, 5, 6]，保持了插入顺序

使用stream流进行去重

List<Integer> list = Arrays.asList(1, 2, 3, 2, 4, 4, 5, 5, 6);  
List<Integer> deduplicatedList = list.stream().distinct().collect(Collectors.toList());  
System.out.println(deduplicatedList); // 输出: [1, 2, 3, 4, 5, 6]

手动去重

List<Integer> list = Arrays.asList(1, 2, 3, 2, 4, 4, 5, 5, 6);  
List<Integer> deduplicatedList = new ArrayList<>();  
Set<Integer> set = new HashSet<>();  
for (Integer item : list) {  if (set.add(item)) { // 如果添加成功，说明是第一次遇到这个元素  deduplicatedList.add(item);  }  
}  
System.out.println(deduplicatedList); // 输出: [1, 2, 3, 4, 5, 6] 

以上四种方式都可以完成对List列表的去重操作，可以根据自己的实际情况任选其一。

9、列表转数组

csList.stream().toArray(String[]::new)