[leetcode]intersection-of-two-arrays-ii 两个数组的交集 II

. - 力扣（LeetCode）

class Solution {
public:vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {sort(nums1.begin(), nums1.end());sort(nums2.begin(), nums2.end());int length1 = nums1.size(), length2 = nums2.size();int index1 = 0, index2 = 0;vector<int> intersection;while (index1 < length1 && index2 < length2) {int num1 = nums1[index1], num2 = nums2[index2];if (num1 == num2) {intersection.push_back(num1);index1++;index2++;} else if (num1 < num2) {index1++;} else {index2++;}}return intersection;}
};