力扣141A

1. 题目链接

Amusing Joke

2. 题目代码

#include<iostream>
#include<string>
using namespace std;int letterOfInt[30];
int letterAtDoorOfInt[30];int main(){string guestName;string hostName;string letterAtDoor;cin >> guestName >> hostName >> letterAtDoor;for(int subscript = 0; subscript < guestName.length(); subscript ++){letterOfInt[guestName[subscript] - 'A'] ++;}for(int subscript = 0; subscript < hostName.length(); subscript ++){letterOfInt[hostName[subscript] - 'A'] ++;}for(int subscript = 0; subscript < letterAtDoor.length(); subscript ++){letterAtDoorOfInt[letterAtDoor[subscript] - 'A'] ++;}bool isOutput = false;for(int subscript = 0; subscript < 26; subscript ++){if(letterOfInt[subscript] != letterAtDoorOfInt[subscript]){cout << "NO";isOutput = true;break;}}if(!isOutput){cout << "YES";}return 0;
}

3. 题目总结

用时：18min

4. 代码分析

参考代码来源：

#include <iostream>
#include <algorithm>
#include <string>using namespace std;
int main(){string s,s1,s2,snew;cin>>s1>>s2>>s;int a=s1.length();int b=s2.length();int c=s.length();if ((a+b)!=c)cout<<"NO"<<endl;else{snew=s1+s2;sort(snew.begin(),snew.end());sort(s.begin(),s.end());if (s==snew)cout<<"YES"<<endl;elsecout<<"NO"<<endl;}
}

我的代码耗时：154ms
内存占用：0KB

参考代码比我的代码解题思路更巧妙