力扣 50.pow(x,n)
class Solution { public: double quickMul(double x,long long N){ if(N0) return 1; double valuequickMul(x,N/2); return N%20?value*value:value*value*x; } double myPow(double x, int n) { long long Nn; return N>0?quickMul(x, N):1.0/quickMul(x, N); } };
2024-09-23